IFPOSInternational Federation of Pediatric Orthopaedic Societies
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5) > ;x [member of] X} is an IFPOS in (X, [tau]), since int (cl[f.
B is an IFOS in (Y, [sigma]), and B is an IFPOS in Y, since B [subset or equal to] int(cl(B)) = B.
alpha], [beta])]) [member of] B, there exists an IFPOS A in X such that [p.