HARH


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AcronymDefinition
HARHHigh Altitude Retinal Hemorrhage
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References in periodicals archive ?
Analogously, we have that HARH([a'.sub.b'], [b'.sub.a'], [b'.sub.f],[f.sub.b']), HARH ([f.sub.b'],[b'.sub.f],[b'.sub.e'],[e'.sub.b']), HARH([e'.sub.b'],[b'.sub.e'][b'.sub.d],[d.sub.b']), and HARH ([d.sub.b'],[b'.sub.d], [b'.sub.c'], [c'.sub.b']) imply HARH([c'.sub.b'], [b'.sub.c'], [b'.sub.a'],[a'.sub.b']), and HARH([b'.sub.c'], [c'.sub.b'], [c'.sub.d], [d.sub.c']), HARH([d.sub.c'], [c'.sub.d],[c'.sub.f'],[f'.sub.c']), HARH([f'.sub.c'],[c'.sub.f'][c'.sub.e],[e.sub.c']), and HARH([e.sub.c'], [c'.sub.e], [c'.sub.a'], [a'.sub.c']) imply HARH([a'.sub.c'], [c'.sub.a], [c'.sub.b'], [b'.sub.c']).
These obtained three halves of affine regular hexagons HARH([b'.sub.a'], [a'.sub.b'], [a'.sub.c'],[c'.sub.a']), HARH([c'.sub.b'],[b'.sub.c'],[b'.sub.a'],[a'.sub.b']), and HARH ([a'.sub.c'], [c'.sub.a'], [c'.sub.b], [b'.sub.c']) determine the affine regular hexagon ARH([b'.sub.a'],[a'.sub.b'],[a'.sub.c'], [c'.sub.a'],[c'.sub.b'],[b'.sub.c']) (Figure 19).