IKX

AcronymDefinition
IKXInternational Knowledge Exchange
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[H.sup.i] = exp (ikz cos [theta] + ikx sin [theta]) {- cos [theta][e.sub.x] + sin [theta][e.sub.z]}, (27)
[E.sub.i] = exp (ikz cos [theta] + ikx sin [theta]) {cos [theta][e.sub.x] - sin [theta][e.sub.z]},
[p.sup.v.sub.2] = - ([D.sub.k] cosh ky + [F.sub.k] sinh ky) exp [(ikx - i[omega]t)].
[[??].sub.fd] = [1/[(ik).sup.[alpha]] [(ikx).sup.[alpha]][??]] (8a)
[[partial derivative].sup.2]/[partial derivative][x.sup.2] exp(ikx) = -[k.sup.2] x exp(ikx).
[1/2[pi]] [[infinity].summation over (k=-[infinity])] exp (ikx) = [[infinity].summation over (n=-[infinity])] [delta] (x - 2[pi]n), (57)