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For example, when our scheme selects the shortest RQ to route (JSQ), it can be regarded as selecting "best" relay.
Since [pi] performs JSQ, [Y.sub.[n]](t) is incremented by 1.
There are [xi] more customers in the SQ under [??], and if we distribute those [xi] customers to the RQ in the "waterfilling" manner (equivalently, route [xi] customers one after another using JSQ) and denote the resulting vector of RQs by [??]'(t), then we have [mathematical expression not reproducible].
Note that Y(t + 1) is obtained by performing the JSQ routing to Y(t).
We have [??](t+1) - X(t+1) = [xi] = 1; clearly, (2) is the JSQ operation on Y(t) with a single customer under [pi], and (3) is also the JSQ operation on [??](t) with [xi] = 1 customer under [??].
(3) Perform JSQ of a customer from X(t) and [??] (t) so as to yield Y(t + 1) and [??]'(t + 1), respectively
Since both Y(t + 1) and [??]'(t+ 1) are formed by performing JSQ routing to [mathematical expression not reproducible].
(1) T(The present Flemish JSQ was formed in 1946 and has persisted since that time) iff the present Flemish JSQ was formed in 1946 and has persisted since that time.
(3) [T.sub.F1] (The present Flemish JSQ was formed in 1946 and has persisted since that time).
Both the Flemish and the Flamish JSQs exist in the one and only world there is, according to the magical antirealist.
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- JSR 114
- JSR 127
- JSR 152
- JSR 154
- JSR 199
- JSR 215
- JSR 221
- JSR 245
- JSR 252
- JSR 54
- JSR 56
- JSR 913
- JSR 914
- JSR 924
- JSRC CENTRE